1) The standard molar entropy value of N2 (g) is 191.5 J/K-mol,

Question

of O2 (g) is 205.0 J/K-mol and of NO2 (g) is 240.0 J/K-mol. From these values we can calculate the Delta So for the reaction N2 (g) + 2 O2 (g)-> 2 NO2 (g) to be?

I did products - reactants

(240 X 2) - [191.5 + (250 X 2)]
480 - 601.5 = -121.5

The delta S is -121.5

2) Calculate the value of delta Go for the reaction , given the standard free energies of formation listed below each ion.

Ag(SO3)_2^3- -> Ag^+ + 2SO3^2-

delta Gfo, kJ/mol for Ag(SO3)_2^3- is -943 , for Ag^+ it is +77 and for 2SO_3^2- it is -497.

I did products - reactants

[(-497 X 2) + 77] - (-943)]

-917 - (-943) = 26

The delta g is +26.

Are my answers correct? Thank you!

Answer 1

I remember this from a day or so ago. I think these are the answers I obtained then although I didn't go through them again today. Note you made a typo in calculation of dS. 2*250 you meant to type 2*205. But the answer is ok.