#1) The Lewis structure of PF3 shows that central phosphorus atom has ___ nonbonding and ___ bonding electron pairs.
#2) How many equivalent resonance forms can be drawn for CO3^-2? (carbon is the central atom)
#3) The bond angle in NF3 is slightly less than ___?
#4) Sample of gas (1.3mol) occupies ____L at 22 Celcius and 2.5 atm.
6 answers
I would be interested in knowing what you think about these questions and why? We are not in the habit of doing all of the homework. Show what you have done on a problem and we can help you through it.
I am trying to study for my final exam. I am just trying to do my review packet and i just want to see if i am getting them correct.
but what i got was
1) 3,3
2) 2
3) 120
4) idk how to do that one.
but what i got was
1) 3,3
2) 2
3) 120
4) idk how to do that one.
For PF3, I think P has 1 non-bonding pair and 3 bonding pairs. Here is a site that gives the Lewis structure for PF3. PF3 is closer to the bottom of the page.
(Broken Link Removed)
(Broken Link Removed)
#2. For CO3^-2, I would think there are three equivalent structures. You MAY have meant two + the original (which makes 3) but equivalent means all of them. All of them are resonance forms of each other.
We can't draw these things on the board but here is a site that does a nice job.
http://www.chem.ucla.edu/~harding/tutorials/resonance/draw_res_str.html
We can't draw these things on the board but here is a site that does a nice job.
http://www.chem.ucla.edu/~harding/tutorials/resonance/draw_res_str.html
NF3, Lewis structure wise, looks much like PF3. The electronic geometry, therefore, is tetrahedral (1 lone pair, and 3 pairs of bonded electrons). [Four regions of high electron density gives a tetrahedral structure.] The lone pair occupies more space; therefore, the tetrahedral bond angle of 109o is reduced somewhat. So I think the answer should be "slightly less than 109o. Here is a site that talks about that.
http://answers.yahoo.com/question/index?qid=20061129055540AAOTWwD
http://answers.yahoo.com/question/index?qid=20061129055540AAOTWwD
#4. First, note the correct spelling of celsius.
Use PV = nRT.
P is in atmospheres (2.5), V is the only unknown (in liters), n is the number of moles (1.3), R is the universal gas constant of 0.08205 L*atm/mol*K, and T is the temperature in Kelvin (273+22 = 295 K
Use PV = nRT.
P is in atmospheres (2.5), V is the only unknown (in liters), n is the number of moles (1.3), R is the universal gas constant of 0.08205 L*atm/mol*K, and T is the temperature in Kelvin (273+22 = 295 K
1 answer