A. Equation 1:
P = 2L + 2W
24 = 2(2W) + 2W
24 = 6W
4 = W
? = L
A = LW
1. The length of a rectangle is twice its width. The perimeter of the rectangle is 24 inches. Write a system of equations in 2 variables. Use substitution to solve the problem.
A. Equation 1:
Equation 2:
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B. What is the area of the rectangle?
1 answer