1a. Fnet = M*a.
Fnet = M*0,
Fnet = 0.
b. F - Fk = M*a.
2500 - Fk = M*0 = 0,
Fk = 2500 N. = Force of kinetic friction.
2. F = M*a.
a = F/M
The Eq, a = F/M, states that if we double M, the acceleration will be cut in
half.
1. The image shows a man pulling a truck. If it does not show up for you for whatever reason, this is a description of the image.
Assume it takes 2500 N for him to pull the truck along the road at a constant speed.
a. Find the net force acting on the truck. (1.5 points)
b. Find the force of friction acting on the truck. (1.5 points)
2. Find the acceleration of a 10 N on a 10kg mass. How does it compare to the acceleration if you double the force on an object that is double the mass? Support your answer with work. (3 points)
3. How much pressure are you exerting on the ground when you are standing on one foot? (Assume your shoes are rectangular shaped.)
* convert to S.I. Units. (6 points)
1 answer
1 answer