if they are inverses, then f(g(x)) = g(f(x) = 1
So, what do we have?
f(g) = 3g-7 = 3((x+3)/7)-7 ≠ x
Note that if g = (x+7)/3, then f = g-1
1. The following functions are inverses of each other: f(x) = 3x - 7 and g(x)= x+3 / 7
False, right?
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