Type divisions this way ...
C = 6000/(300-x)
a) replace x with 75
C = 6000/(300-3(75))
= 6000/75 = 80
b) you try it, should get 200
c) should be really high
d) what happens when x = 100 ?
1. The cost, in millions of dollars, to remove x % of pollution in a lake modeled by C = __6,000__ (all supposed to be underlined)
300-3x
a. What is the cost to remove 75% of the pollutant?
b. What is the cost to remove 90% of the pollutant?
c. What is the cost to remove 99% of the pollutant?
d. For what value is this equation undefined?
e. Do the answers to sections a. through d. match your expectations? Explain why or why not.
4 answers
For A...I have 80million
B...200million
C...58 million
B...200million
C...58 million
c)
C = 6000/(300 - 3(99))
= 6000/3
= 2000 million
C = 6000/(300 - 3(99))
= 6000/3
= 2000 million
ok i did it like this:
6000/(300-3*99)
oh!!! never mind got it now..thank you!!!!
6000/(300-3*99)
oh!!! never mind got it now..thank you!!!!