1. Tasha and Lee played a series of games against each other. Tasha won three more than twice as many games as Lee. Lee won 15 games. Find the probability that Tasha won a game.

Question

*
1 point
15/35
15/48
33/48
2/15

Answer 1

To find the probability that Tasha won a game, we need to first calculate how many games Tasha won.

Given that Tasha won three more than twice as many games as Lee, and Lee won 15 games, we can calculate Tasha's total number of wins:

2 * 15 = 30
30 + 3 = 33

Tasha won 33 games.

Now, to find the probability that Tasha won a game, we need to consider the total number of games played by both Tasha and Lee:

33 (Tasha's wins) + 15 (Lee's wins) = 48 (total games played)

The probability that Tasha won a game is given by:

P(Tasha won a game) = Tasha's wins / total games played
P(Tasha won a game) = 33 / 48
P(Tasha won a game) = 33/48

Therefore, the probability that Tasha won a game is 33/48.

The answer is: 33/48.