1. I would fill the cylinder about half full of water, read the volume, drop in 5 marbles, read the volume. The volume of 5 marbles is the difference in the two readings and the volume of olne marble is the total volume divided by 5.
2. The beaker is 24.68g - 0.15 g = ?g
3. I don't know what you did with the numbers. Probably you calculasted the volume from volume = mass H2O/density
There is a shorter way but I would
calculate volume using 0.997 for what we'll call 1 and do it again using 1.00 for density. Call that one 2.
[(volume for 1-volume for 2)/volume 1)]*100 = %error.
1. Suppose you have a box of 10 marbles, a 50mL gradulated cylinder, and some water. How would you measure the volume of a marble? (Assume that all marbles are equal volume.)
2. Suppose a digital balance reads 0.15g when is placed on the balance and the balance reads 24.68g, what ia the true mass of the beaker?
3. The density of water at 25 degrees is 0.997 g/mL. What % error would you make if you used the value of 1.000g/mL at 25 degree Celcius? (Show your calculations)
2 answers
a liquid has a volume of 3.70 L what is its volume in ML? IN CM3?