The answer is 20.
To solve this problem, you can use the combination formula:
nCr = n! / r!(n-r)!
In this case, we want to find 6C3, which represents the number of ways to choose 3 items from a set of 6 items. Using the formula:
6C3 = 6! / 3!(6-3)! = 6! / 3!3! = (6 × 5 × 4) / (3 × 2 × 1) = 20
Therefore, the answer is 20.
1. Solve:
6C3
• 120
• 720
• 20
• 240
1 answer