1)Solve 3+2(1-x)>6 or 2x+14<=8. Graph the solution set on a number line.
The number line I'm working with is:
-4 -3 -2 -1 0 1
First solution:
3+2-2x>6
5-2x>6
-2x>1
x> -1/2
for the graph, I have an open circle between 0 and 1 and the arrow going right.
Second solution:
2x+14<=8
2x<= -6
x<= -3
for the graph, I have a closed circle on the -3 and the arrow going left.
2 answers
seem right to me.
You made an error in the first part.
for the first one you had
-2x>1
x> -1/2
when you divide by a negative, the inequality sign has to be reversed, so it is
x < -1/2
so that would be an open circle at -1/2 and the line going to the left.
since your relations are joined with OR and the second one is x < -3
the actual solution would be the first graph above.
for the first one you had
-2x>1
x> -1/2
when you divide by a negative, the inequality sign has to be reversed, so it is
x < -1/2
so that would be an open circle at -1/2 and the line going to the left.
since your relations are joined with OR and the second one is x < -3
the actual solution would be the first graph above.
8 answers