Ask a New Question

1. Solve: 2 cos² x - 3 cos x + 1 = 0 for 0 ≤ x < 2pi.

2. Solve: 2 sin x - 1 = 0 for 0° ≤ x < 360°

3. Solve: sin² x = cos² x for 0° ≤ x < 360°

4. Solve: sin x - 2sin x cos x = 0 for 0 ≤ x < 2pi.

Ask a New Question or answer this question.

Similar Questions

If S=1/2^2cos1 + 1/cos1¤cos2+1/2^3 cos1 ¤cos2¤cos2^2 + .......... upto 10 terms . If S= sina(cotb-cotc) where a,b,c€N Then
1. 2 answers
1. Solve: 2 cos² x - 3 cos x + 1 = 0 for 0 ≤ x < 2pi.2. Solve: 2 sin x - 1 = 0 for 0° ≤ x < 360° 3. Solve: sin² x =
1. 0 answers
Which expression is equivalent to (sin x + 1)(sin x − 1)?A. cos2^x B. -cos2^x C. cos2^x + 1 D. cos^2x − 1 E. -cos^2x + 1
1. 1 answer
Blake is told that an angle has a cosine of −16√and is in Quadrant III. Use the Pythagorean identity sin2(θ)+cos2(θ)=1 ,
1. 1 answer

more similar questions