1. Sin δ = ( cos δ + 200 )

3 answers

since cosx = sin(90-x),
cos(x+200) = sin(90-(x+200)) = sin(-110-x)
so, x = -110-x
x = -55
check: sin(-55) = -sin(55) = -cos(35) = cos(145)
Sin δ = Cos δ + 200
Sin δ = Cos ( 900 - ( δ + 200 ) )
δ = 900 - δ - 20
2δ = 70
δ = 350
sorry its 90 not 900