1.Simplify x/7x+x^2

Question

A.1/7+x;where x≠-7
B.1/7x;where x≠0
C.1/7+x;where x≠0,-7
D.1/7****

2.Simplify -12x^4/x^4+8x^5
A.-12/1+8x;where x≠-1/8****
B.-12/1+8x;where x≠-1/8,0
C.-12/9x;where x≠0
D.-12/9

3.Simplify x^2-3x-18/x+3
A.x-3
B.x-6;where x≠-3
C.x-6;where x≠6
D.1/x+3;where x≠-3****

4.Simplify 7/2a•5/a^2
A.35/2a^2;where a≠0
B.35/2a^2****
C.12/2a^3;where a≠0
D.35/2a^3;where a≠0

5.Multiply
x-5/4x+8•(12x^2+32x+16)
A.(3x+2)/4(x-5)
B.(x-5)(3x+2)/4****
C.(x-5)(3x+2)
D.(x-5)(12x+8)

I think the answers for 1-5 are:
1.D
2.A
3.D
4.B
5.B

Answer 1

You have mangled your expressions. I cannot parse them at all. I suggest you go to

wolframalpha.com

and type in your expressions. Watch to see how they get interpreted, and use parentheses till you get what you expect.

Answer 2

Well I have the same question for the first one. It is x/7x+x^2

Answer 3

answer for one is either a or c

Answer 4

The answer is C, 1/7+x; where x≠0,-7.

Here's the explanation:

We can factor the denominator in the expression:

x/7x + x^2 = x/(x(7 + x))

Now we can simplify the expression:

x/(x(7 + x)) = 1/(7 + x)

However, we need to be careful with this simplified expression. We know that x cannot be equal to 0 or -7, because these values would make the denominator 0. So, the final simplified expression is:

1/7 + x; where x≠0,-7