draw your triangle in standard position. Since cotπΌ = x/y, you have
x = -21β2
y = 1
so, since r^2 = x^2+y^2, r = β883
Now the rest is easy, since
sinπΌ = y/r
cosπΌ = x/r,
and so on.
Why do I suspect a typo? Could it be that cotπΌ = 2/β2 = -β2 ?
If so, then fix the values for y and r, and do the calculations accordingly.
(1 point) Given cot(πΌ)=β21β2 and π/2<πΌ<π, find the exact values of the remaining five trigonometric functions.
Note: You are not allowed to use decimals in your answer.
1 answer