Degrees of freedom for this type of t-test is this:
df = n1 + n2 - 2
1)Please Help In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows: Assume that the population variances are equal. Then, the Pooled Variance is equal to: A) 0.1017
B) 1.2713
C) 0.3189
D) 1.1250
2-. Two samples of sizes 25 and 35 are independently drawn from two normal populations, where the unknown population variances are assumed to be equal. The number of degrees of freedom of the equal-variances t test statistic is: A) 60
B) 59
C) 35
D) 58
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