Asked by jade
1. Papa Tom Smurf is a smurf-player. He wants to take two smurfettes out on a date. There are 3 blue smurfettes, 5 navy smurfettes and 2 turquoise smurfettes.
a) What’s the probability that the smurfettes he dates are of different colours? (4)
b) If he instead takes three smurfettes out on a date, what’s the probability that they are all of the same colour? (3)
I am extremely confused with probability, can someone please help?
a) What’s the probability that the smurfettes he dates are of different colours? (4)
b) If he instead takes three smurfettes out on a date, what’s the probability that they are all of the same colour? (3)
I am extremely confused with probability, can someone please help?
Answers
Answered by
Reiny
Blue -- B --- 3
Navy -- N -- 5
Turquoise -- T -- 2
a) his choices could be BN, BT, OR NT
prob(Blue Navy) = C(3,1) C(5,1)/C(10,2) = 3*5/45 = 1/3
prob(B T) = C(3,1) C(2,1)/C(10,2) = 6/45 = 2/15
prob(N T) = ...
add them up
or
Prob(B N) = (3/10) (5/9) (2) , times 2 because it could be BN or NB
= 30/90 = 1/3
etc for the other two
b) 3 of the same colour, implies it can only be BBB or NNN
combination way:
prob(BBB) = C(3,3)/C(10,3) = 1/120
other way:
prob(BBB) = (3/10)(2/9)(1/8) = 6/720 = 1/120
find NNN in the same way, then add them up
Navy -- N -- 5
Turquoise -- T -- 2
a) his choices could be BN, BT, OR NT
prob(Blue Navy) = C(3,1) C(5,1)/C(10,2) = 3*5/45 = 1/3
prob(B T) = C(3,1) C(2,1)/C(10,2) = 6/45 = 2/15
prob(N T) = ...
add them up
or
Prob(B N) = (3/10) (5/9) (2) , times 2 because it could be BN or NB
= 30/90 = 1/3
etc for the other two
b) 3 of the same colour, implies it can only be BBB or NNN
combination way:
prob(BBB) = C(3,3)/C(10,3) = 1/120
other way:
prob(BBB) = (3/10)(2/9)(1/8) = 6/720 = 1/120
find NNN in the same way, then add them up
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