1. Not sure of how to do the calculations...
Make a 0.200 m solution of NaCl in a 100. mL volumetric flask. ... Solution A's question or statement is the same but with M (molarity)
Is this right? The small m means molality. If it were changed to capital M, then solution A's MOLARITY is 1.17 g. Would both solutions be the same ?
0.1 L * (0.200 m NaCl/1L)*(58.443 g NaCl/1 mole NaCl) = 1.17 g NaCl
Would Sol'A contain more, less, or same moles of solute (NaCl)?
And finally, Is the volume of Sol A more, less, or the same as the volume of Sol'B? Why?