1. Nitric acid is produced via the following equation: 3 NO2 + H2O = 2HNO3 + NO. How many grams of NO2 are required to produce 7.5 grams of HNO3?

Answer 1

Dear Brett,
molar mass of the HNO3= 1+14+16x3
=63

number of moles of the HNO3 produced in the reaction = 7.5/63
= 0.119

According to the equation provided 3 moles of NO2 will produce 2 moles of HNO3
Thus,number of moles of NO2 required=
0.119/2x3
= 0.179

mass of N02 required=
0.179x(14+32)
= 8.214g

Therefore, 8.214 grams of N02 is required

Hope it helps:)

Answer 2

The answer should be 8.24 not 8.214