1 mole of chlorine combines with a certain weight of a metal giving 111g of its chloride. The atomic weight of the metal (assuming its valency to be 2) is-

Answer 1

M = metal
we have MCl2
1 mol chlorine and 1/2 mol of metal
35.5 g chlorine in a mol

111 - 35.5 = 75.5 g of M

so M is 75.5 * 2 = 151 g/mol

maybe Europium