Let's go through each question one by one.
2. Find \( m \) in the equation \( \frac{1}{2} m - \frac{3}{4} n = 16 \) when \( n = 8 \).
Substituting \( n = 8 \):
\[
\frac{1}{2} m - \frac{3}{4} (8) = 16
\]
Calculating \( \frac{3}{4} \times 8 = 6 \):
\[
\frac{1}{2} m - 6 = 16
\]
Adding 6 to both sides:
\[
\frac{1}{2} m = 22
\]
Multiplying both sides by 2:
\[
m = 44
\]
Value of \( m \): 44
3. Librarian's DVD Budget
The cost equation is:
\[
20x + 8y = 500
\]
Now we examine each option:
-
\( x = 8, y = 45 \):
\[
20(8) + 8(45) = 160 + 360 = 520 \quad (\text{over budget})
\]
-
\( x = 10, y = 22 \):
\[
20(10) + 8(22) = 200 + 176 = 376 \quad (\text{under budget})
\]
-
\( x = 16, y = 22 \):
\[
20(16) + 8(22) = 320 + 176 = 496 \quad (\text{under budget})
\]
-
\( x = 18, y = 18 \):
\[
20(18) + 8(18) = 360 + 144 = 504 \quad (\text{over budget})
\]
Possible choices: \( x = 10, y = 22 \) or \( x = 16, y = 22 \) (Budget allowed)
4. Find \( x \) in the equation \( 4x + 8y = 40 \) when \( y = 0.8 \).
Substituting \( y = 0.8 \):
\[
4x + 8(0.8) = 40
\]
Calculating \( 8 \times 0.8 = 6.4 \):
\[
4x + 6.4 = 40
\]
Subtracting 6.4 from both sides:
\[
4x = 33.6
\]
Dividing both sides by 4:
\[
x = 8.4
\]
Value of \( x \): 8.4
5. Find \( x \) in the equation \( 8x - 2y = 48 \) when \( y = 4 \).
Substituting \( y = 4 \):
\[
8x - 2(4) = 48
\]
Calculating \( 2 \times 4 = 8 \):
\[
8x - 8 = 48
\]
Adding 8 to both sides:
\[
8x = 56
\]
Dividing both sides by 8:
\[
x = 7
\]
Value of \( x \): 7
6. Error in Barbara's equation
The equation is meant to consider the number of bottles sold:
\[
1.25x + 1.49y = 100
\]
Since she only included the iced tea price but not the number of bottles of water \( y \), the correct interpretation requires that both prices multiply their respective quantities.
Error: Barbara’s equation did not consider the number of bottles of water.
7. Find \( x \) in the equation \( 2x + 3y = 36 \) when \( y = 6 \).
Substituting \( y = 6 \):
\[
2x + 3(6) = 36
\]
Calculating \( 3 \times 6 = 18 \):
\[
2x + 18 = 36
\]
Subtracting 18 from both sides:
\[
2x = 18
\]
Dividing both sides by 2:
\[
x = 9
\]
Value of \( x \): 9
8. Find \( y \) in the equation \( 5x + 2y = 20 \) when \( x = 0.3 \).
Substituting \( x = 0.3 \):
\[
5(0.3) + 2y = 20
\]
Calculating \( 5 \times 0.3 = 1.5 \):
\[
1.5 + 2y = 20
\]
Subtracting 1.5 from both sides:
\[
2y = 18.5
\]
Dividing both sides by 2:
\[
y = 9.25
\]
Value of \( y \): 9.25
9. Find \( x \) in the equation \( \frac{1}{5}x - \frac{2}{3}sy = 30 \) when \( y = 15 \).
Note: Let's assume \( s \) just represents a constant scalar for this example; without \( s \) known it's not possible to solve for \( x \) directly.
Substituting \( y = 15 \):
\[
\frac{1}{5}x - \frac{2}{3}s(15) = 30
\]
Which leads to \( \frac{2}{3} \times 15 = 10 \):
Rearranging it becomes \( \frac{1}{5}x - 10s = 30 \) - to solve correctly would need value for \( s \).
The question's answer options suggest we don’t know; we could assume no correct answer is available without assuming \( s \).
10. Chen's Veggies and Fruits
Using cost equation:
\[
5v + 7(2.85) = 28.70
\]
Calculating \( 7 \times 2.85 = 19.95 \):
\[
5v + 19.95 = 28.70
\]
Subtracting 19.95 from both sides:
\[
5v = 28.70 - 19.95 = 8.75
\]
Dividing by 5:
\[
v = 1.75
\]
Approximate price of a pint of veggies: $1.75
In summary:
- 44
- \( x = 10, y = 22 \) or \( x = 16, y = 22 \)
- 8.4
- 7
- Barbara's error: Number of water bottles.
- 9
- 9.25
- (Requires value of \( s \))
- $1.75