1. logaB = 2 and logbC = 4, evaluate logcA
*the lowercase letters are bases ie. log(base a)B
2. solve for x: (log(base 2)x))^3 = log(base 2)x
*the lowercase letters are bases ie. log(base a)B
2. solve for x: (log(base 2)x))^3 = log(base 2)x
1 answer
1 answer
1 answer
1 answer