1) log n + log 5 = 3

Question

2) log y = 1/3 [log40 - log5] + 2/3 log27 + log11

Answer 1

log 5n = 3
assuming base 10 logs,
5n = 10^3 = 1000
n = 200

log y = 1/3 log(40/5) + 2/3 log 27 + log 11
since 8 = 2^3 and 27 = 3^3, that is
log y = log 2 + 2 log 3 + log 11
log y = log(2*9*11)
y = 2*9*11