Perhaps you mean
Lim (x^3-125)/(x^2-25)
x->5
Since the expression approaches 0/0 at x=5, take the ratio of derivatives, which is 3x^2/2x = 1.5 x. The limit is therefore 7.5 when x->5
This method is called using L'Hopital's rule.
(1) lim x^3 - 125/x--;5 x^2 - 25
1. Lim as x approaches what? arrow sign
1 answer