#1 a unit vector in the direction of w is
z=[3/5;4/5]
p = u.z = 11/5 z = [33/25;44/25] = [1.32;1.76]
you are correct
|kp| = k|p| = 55/25 k
So, k = 25/55
As for the span, that is usually defined for a set of vectors. span{w} would just be w. So, any vector orthogonal to w will work.
1)let w=[3;4] and u=[1;2]
a) find the projection p of u onto w. I found this to be p=[1.32;1.76]
b) find a scalar k for which the vector kp has a norm that is equal to one. k=?
d)find a vector that is orthogonal to span{w} s=?
how do I do this
3 answers
could you explain how you got 55/25
you know p. Can you not figure its length?
√(33^2+44^2) = 55
√(33^2+44^2) = 55
4 answers