RT = RS + ST = 15.
(2m+2) + (3m+3) = 15.
m = ?.
1. Let S be between R and T. Use the Segment Addition Postulate to solve for m.
RS = 2m + 2
ST = 3m + 3
RT = 15
A. m = 3
B. m = 2
C. m = 9
D. m = 4
2 answers
D.4