1. Joe has 37 coins (all nickels, dimes and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Joe have?

Answer 1

number of nickels ---- x
number of quarters -- x+4
number of dimes = 37-(x+x+4) = 33 - 2x

5x + 25(x+4) + 10(33-2x) = 550
solve for x

let me know what you get

Answer 2

I got:
Nickels - 12
Quarters - 16
Dimes - 9

I was not sure how to set up the problem. I'm good with two variables but not three.

thx