a. X + Y = 78.
b. Y = 2X.
c. Eq1: X + Y = 78.
Eq2: Y = 2X.
In Eq1,substitute 2X for Y:
X + 2X = 78,
3X = 78,
X = 26 Homes with the 1st floor plan.
In Eq2, substitute 26 for X:
Y = 2*26 = 52 Homes with the 2nd floor plan.
d. X + Y = 78.
When X = 0,
Y = 78 = Y-Intercept.
When Y = 0,
X = 78 = X-Intercept.
Y = mx + b, The slope int. form.
Y = 2X + 0.
The Y-Int. = 0.
When Y = 0,
X = 0 = X-Int.
Solution set:(X,Y)= (26,52).
The solution set is the point where the
lines intersect.
1. Imagine you are in the market for a new home and are interested in a new housing community under construction in a different city.
a. The sales representative informs you that there are 78 houses for sale with two floor plans still available. Use x to represent floor plan one and y to represent floor plan two. Write an equation that illustrates the situation.
b. The sales representative later indicates that there are twice as many homes available with the second floor plan than the first. Write an equation that illustrates this situation. Use the same variables you used in Part a.
c. Use the equations from Parts a. and b. of this exercise as a system of equations. Use substitution to determine how many of each type of floor plan is available. Describe the steps you used to solve the problem.
d. What are the intercepts of the equation from Part a. of this problem? What are the intercepts from Part b. of this problem? Where would the lines intersect if you solved the system by graphing?
1 answer
1 answer