2 h = 10 - 5 r
5 r = 10-2h
r = 2 -(2/5) h
v = h(6 - (1/3)(2 - (2 h/5))^3 )
Yuck, you can multiply it out
ln x^x = x ln x = x y
but
e^y = x
so
ln x^x = y e^y
#1
If
v=(6-(r^3/3))h and h/(2-r)=5/2
write V as a function of h .
Simplify the function so that you can express it as a polynomial in h .
#2
If y=ln(x) , write ln(x^x) as a simple function of y
thxs alot!
1 answer
1 answer