Asked by Chen

1. if the largest of three consecutive even integers is multiplied by 5, the product is 6 less than three times the sum of the first two integer. fin the integers.
Answered by Steve
(x+4)5 = 3(x + x+2)-6

Now just find x, the smallest number.
Answered by Erza
5(x+4)=3(2x+2)-6
5x+20=6x+6-6
5x+20=6x
5x-6x=-20
-x=-20
x=20
Answered by Erza
5(x+4)=3(2x+2)-6
5x+20=6x+6-6
5x+20=6x
5x-6x=-20
-x=-20
x=20

x+2=22
x+4=24

20,22,24
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