I don't think #1 is right so I believe you should rethink your other answers although I didn't look at them after #2. My reason for this response is
I assume the procedure went something like this.
(initial mass alum - final mass alum) = loss in mass and that is mass H2O released.
Then (mass H2O/mass sample)*100 = %H2O
Since some of the alum splattered out, the final weight is lower than it should be which makes the loss mass more which makes the apparent amount of H2O larger and that gives a larger % H2O.
#2 is right.
1. If alum is heated at first too strongly causing it to splatter out of the crucible what effect will this have on the determination of the water hydration?
2. If alum is heated insufficiently what effect will this have on the determination of the water hydration?
3. If not all the alum dissolves in the water before adding the Ba(NO3)2 solution, what effect will this have on the sulfate percent error determination?
4. If precipitation of BaSO4 is incomplete due to inadequate heating or insufficient time what will happen to the sulfate percent error determination? 5. If the BaSO4 ppt isn't washed adequately what effect will this have on the sulfate percent error determination?
6. If the BaSO4 ppt isn't dried completely what effect will this have on the sulfate percent error determination?
I know it is alot but I need some help. Are my answers correct? Thanks! :)
Answers:
1. The water of hydration will be will be lower because some alum was released from the crucible.
2. The water of hydration will be lower.
3. The percent of error will be higher.
4. Percent of error will be higher.
5. Percent of error will be higher.
6. Percent of error will be higher than the actual.
1 answer