Your calculations for the volume of the spherical chocolate truffle are generally correct, but let’s reorganize and verify the computation step-by-step:
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Identify the Given Values:
- Radius (\( r \)) = 12 mm
- Approximation for \( \pi \) = 3.14
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Substitute the Values Into the Formula for Volume of a Sphere:
The formula for the volume \( V \) of a sphere is given by:
\[ V = \frac{4}{3} \pi r^3 \]
Substituting the known values:
\[ V = \frac{4}{3} * 3.14 * (12)^3 \]
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Calculate \( 12^3 \) (12 cubed):
\[ 12^3 = 12 * 12 * 12 = 1728 \]
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Plug the Values into the Formula:
\[ V = \frac{4}{3} * 3.14 * 1728 \]
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Multiply the Values:
- Start by calculating \( 4 * 1728 \):
\[ 4 * 1728 = 6912 \]
- Next, multiply \( 6912 * 3.14 \):
\[ 6912 * 3.14 = 21727.68 \]
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Divide by 3:
Now, divide \( 21727.68 \) by 3 to finalize the volume:
\[ V = \frac{21727.68}{3} \approx 7242.56 \]
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Round to the Nearest Hundredth:
The volume of the chocolate truffle, rounded to the nearest hundredth, is approximately 7242.56 mm³.
Therefore, the amount of chocolate in the spherical truffle is approximately 7242.56 mm³.
Your initial rounding step was not accurate; the correct final answer is 7242.56 mm³.