1. F = 4 * 30000N = 120000N.
F = ma = 120000,
31600*a = 120000,
a = 120000 / 31600 = 3.8 m/s^2.
2. F = ma,
m1 = F/a,
m2 = 5F/a,
m2/m1 = (5F/a) / (F/a) = 5F/a * a/F =
5F/F = 5/1.
1. How much acceleration does a 747 jumbo jet of mass 31600 kg experience in takeoff when the thrust for each of four engines is 30000 N?
2. Two boxes are seen to accelerate at the same rate when a force F is applied to the first and 5F is applied to second. What is the mass ratio of the boxes?
3 answers
1.) a=f/m; f= 30,000 N and m= 30,000 kg; you must do 30,000 N * 4 = 120,000 N because there are 4 jets that are each 30,000 N; a= 120,000 N / 30,000 kg = 4 m/s^2
(4 x 30000)/31600 should get you your answer to 1