5% v/v solution means 5 mL H2O2 in 100 mL solution; therefore, in 969 mL solution there will be 5 x (969/100) =?? ml H2O2.
m = moles/kg solvent.
1.35 m means 1.35 moles CaCl2/kg solvent.
So you have 1.35 moles CaCl2.
Calculate moles water in 1 kg water.
mole fraction CaCl2 = moles CaCl2/total moles.
1)How many mL of H2O2 are in 969 mL in solution ? * Given: 5.0% of H2O2 by volume.
2)What is the mole fraction of the solute in a 1.35m solution of CaCl2?
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