To determine the volume of the 0.010 M copper(II) sulfate solution needed to prepare 100.00 milliliters of a 0.00020 M copper(II) sulfate solution, we can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of copper(II) sulfate solution before dilution = 0.010 M
V1 = volume of copper(II) sulfate solution before dilution (unknown)
C2 = concentration of copper(II) sulfate solution after dilution = 0.00020 M
V2 = volume of copper(II) sulfate solution after dilution = 100.00 mL
Plugging in the values, we get:
(0.010 M)(V1) = (0.00020 M)(100.00 mL)
Solving for V1:
V1 = (0.00020 M)(100.00 mL) / 0.010 M
V1 = 2.00 mL
Therefore, approximately 2.00 milliliters of the 0.010 M copper(II) sulfate solution is needed to prepare 100.00 milliliters of a 0.00020 M copper(II) sulfate solution.
1) How many milliliters of the approximately 0.010 M copper(I1) sulfate solution as needed to prepare 100.00 milliliters of a
0.00020 M copper(Il) sulfate solution?
1 answer