1. How many liters of carbon are produced at STP when 295g of methane gas (C3H8) is reacted with excess oxygen? The other products is water vapor. Write out a balanced equation.
My answer:
C3H8+O—-> CO3+OH8?
5 answers
your balanced equation stinks. Products are CO2 and H2O (water vapor)
C3H8 + 5*O2 = 3*CO2 + 4*H2O.
is it methane (CH4) or propane (C3H8) though?? eh, screw it, let's work with propane
1 mole of propane = 44 g - 3 moles of CO2 = 3*44 g
295 g of propane - x g of CO2
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x = (3*44*295)/44 g of CO2 is produces
let me now pretend CO2 is a perfect gas, in which every one of them has a volume of like 22,4 litres per mole
n(CO2) = x g/(44 g/mol) = x/44 moles
V(CO2) = 22,4 L/mol * n(CO2) mole = 22,4*n(CO2) L END
is it methane (CH4) or propane (C3H8) though?? eh, screw it, let's work with propane
1 mole of propane = 44 g - 3 moles of CO2 = 3*44 g
295 g of propane - x g of CO2
---
x = (3*44*295)/44 g of CO2 is produces
let me now pretend CO2 is a perfect gas, in which every one of them has a volume of like 22,4 litres per mole
n(CO2) = x g/(44 g/mol) = x/44 moles
V(CO2) = 22,4 L/mol * n(CO2) mole = 22,4*n(CO2) L END
Is that all that I have to do because I feel as if there’s more for some reason. But if there isn’t can you show me how I should make my balanced equation look?
God can not give you the answer but He can guide you.
did you get an answer?
1 answer