1) How many grams of copper) sulfate pentahydrate (CuSO4 * 5H20) are needed to prepare 100.00 milliters of a 0.10 M

Answer 1

To calculate the amount of copper sulfate pentahydrate needed to prepare a 0.10 M solution in 100.00 milliliters, we can use the formula:

Molarity (M) = moles / volume (L)

First, we need to calculate the moles of copper sulfate needed:

0.10 moles/L = X moles / 0.100 L
X = 0.010 moles of CuSO4

Next, calculate the molar mass of copper sulfate pentahydrate:
Cu = 63.546 g/mol
S = 32.065 g/mol
O = 15.999 g/mol
H = 1.00794 g/mol

(63.546 + 32.065 + (4 x 15.999) + (5 x 1.00794)) = 249.70 g/mol

Now, calculate the grams needed:
0.010 moles x 249.70 g/mol = 2.50 grams

Therefore, 2.50 grams of copper sulfate pentahydrate are needed to prepare 100.00 milliliters of a 0.10 M solution.