don't know what you mean by "simplify". They're already pretty simple.
I see no way to rewrite 3x cos5x
sin2x cos4x = (sin6x + sin2x)/2
but that doesn't look any simpler to me.
any further clarification?
1)how do you simplify 3xcos5x using trigometric functions
2)how do you simplify sin2xcos4x using trigometric functions
8 answers
how did you do sin2x cos4x = (sin6x + sin2x)/2 what os the formula I need to use
Steve help please
use the trig sum-to-difference formulas
sinAcosB = (sin(A+B) + sin(A-B))/2
You must have seen such. If not a visit to
http://oakroadsystems.com/twt/sumdiff.htm
bears study
sinAcosB = (sin(A+B) + sin(A-B))/2
You must have seen such. If not a visit to
http://oakroadsystems.com/twt/sumdiff.htm
bears study
cos3xcos5x
how do rewrie this using trigmetric finctions Steve thanks
how do rewrie this using trigmetric finctions Steve thanks
come on - give it a try using the formulas. What do you come up with?
(cos8x+cos2x)/2 steve is it right
steve