Asked by JESS
                1)how do you simplify 3xcos5x using trigometric functions
2)how do you simplify sin2xcos4x using trigometric functions
            
        2)how do you simplify sin2xcos4x using trigometric functions
Answers
                    Answered by
            Steve
            
    don't know what you mean by "simplify". They're already pretty simple.
I see no way to rewrite 3x cos5x
sin2x cos4x = (sin6x + sin2x)/2
but that doesn't look any simpler to me.
any further clarification?
    
I see no way to rewrite 3x cos5x
sin2x cos4x = (sin6x + sin2x)/2
but that doesn't look any simpler to me.
any further clarification?
                    Answered by
            JESS
            
    how did you do sin2x cos4x = (sin6x + sin2x)/2  what os the formula I need to use
    
                    Answered by
            JESS
            
    Steve help please
    
                    Answered by
            Steve
            
    use the trig sum-to-difference formulas
sinAcosB = (sin(A+B) + sin(A-B))/2
You must have seen such. If not a visit to
http://oakroadsystems.com/twt/sumdiff.htm
bears study
    
sinAcosB = (sin(A+B) + sin(A-B))/2
You must have seen such. If not a visit to
http://oakroadsystems.com/twt/sumdiff.htm
bears study
                    Answered by
            JESS
            
    cos3xcos5x
how do rewrie this using trigmetric finctions Steve thanks
    
how do rewrie this using trigmetric finctions Steve thanks
                    Answered by
            Steve
            
    come on - give it a try using the formulas. What do you come up with?
    
                    Answered by
            JESS
            
    (cos8x+cos2x)/2  steve is it right
    
                    Answered by
            JESS
            
    steve
    
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