1) Graph f(x) = x2−3x+2

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2) f(0) =


3) ​f(1)=

4)​f(2)=

5) The y-intercept is
. Write it as an ordered pair

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Answer 1

To analyze the function \( f(x) = x^2 - 3x + 2 \), we'll calculate the values at specific points and find the y-intercept.

1. Calculate \( f(0) \): \[ f(0) = 0^2 - 3(0) + 2 = 0 + 0 + 2 = 2 \]

2. Calculate \( f(1) \): \[ f(1) = 1^2 - 3(1) + 2 = 1 - 3 + 2 = 0 \]

3. Calculate \( f(2) \): \[ f(2) = 2^2 - 3(2) + 2 = 4 - 6 + 2 = 0 \]

4. Determine the y-intercept: The y-intercept occurs when \( x = 0 \), which we've already calculated. The y-intercept is given as an ordered pair: \[ \text{Y-intercept} = (0, f(0)) = (0, 2) \]

Summary of Results:

• \( f(0) = 2 \)
• \( f(1) = 0 \)
• \( f(2) = 0 \)
• The y-intercept is \( (0, 2) \)