1. Given the functions f(x)=x(cube)-27 and g(x)=x-3, find:

Question

A. (f/g)(x) B.(g/f)(x)

2. Let d(y)=square root of 2x and d(y)=square root of x-1, determine:

A. (d/y)(x) B. (c/d)(x)

Answer 1

c'mon. It's just
(f/g)(x)=f(x)/g(x)=(x^3-27)/(x-3)=x^2+3x+9
naturally that makes it easy to see what (g/f)(x)=g(x)/f(x) is

The next one appears to be mangled.
I shall assume that c(x)=√(2x) and d(x)=√(x-1). Then
(d/c)(x)=d(x)/c(x)=√(x-1)/√(2x) = √((x-1)/(2x))
If I read it wrong, I'm sure you see the pattern by now.