60 ml of H2 at STP is .060/22.4 = 0.0268 moles of H2 formed.
Zn will release H2 in sulfuric acid, but Cu will not.
If you have x grams of Zn and 1-x grams of Cu (total = 1.0 g), the Zn reaction will result in x/65.4 moles of H2.
x/65.4 = 0.00268 moles
x = 0.175
The alloy is 17.5% zinc
1 g alloy of Cu and Zn reacted with excess of H2SO4 gives 60 ml of H2 at STP. What is the % of Zn in the alloy?
1 answer
1 answer