To calculate the area of the rocket ship design, we'll need to break it down based on the given dimensions. From your message, we see the following measurements mentioned:
- Height: 8 ft
- Various other lengths: 1 ft, 4 ft, 4 ft, 2 ft, 5 ft, and 2 ft
However, it's not clear how these dimensions describe the rocket ship. A common interpretation might involve considering these dimensions as forming various geometric shapes like rectangles and triangles to approximate a rocket ship.
Let's consider an example of a simplistic rocket shape that consists of:
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A rectangular body (height = 8 ft, width = 4 ft)
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A triangular top (base = 4 ft, height = 2 ft)
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Additional rectangular sections or fins (you can use the 2 ft and 1 ft dimensions)
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Rectangular Body Area: \[ \text{Area} = \text{Height} \times \text{Width} = 8 , \text{ft} \times 4 , \text{ft} = 32 , \text{sq ft} \]
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Triangular Top Area: \[ \text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} = \frac{1}{2} \times 4 , \text{ft} \times 2 , \text{ft} = 4 , \text{sq ft} \]
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For the fins or any other sections, we will need to clarify the purpose of the other dimensions (2 ft, 1 ft, and 5 ft). Let's say if they are additional rectangles at the bottom:
- Two rectangular fins, each with dimensions 2 ft by 1 ft, for example: \[ \text{Area of 2 fins} = 2 \times (1 , \text{ft} \times 2 , \text{ft}) = 2 \times 2 , \text{sq ft} = 4 , \text{sq ft} \]
Adding these areas together gives us the total area of the rocket design: \[ \text{Total Area} = \text{Area of rectangle} + \text{Area of triangle} + \text{Area of fins} \] \[ \text{Total Area} = 32 , \text{sq ft} + 4 , \text{sq ft} + 4 , \text{sq ft} = 40 , \text{sq ft} \]
Thus, the area the rocket ship design takes up is 40 square feet.
If this interpretation does not match your requirements or if there are more details about the rocket shape, please provide those, and I can adjust the calculations accordingly!
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