1. pick a number -- x
2. multiply by 2 -- 2x
3. add 5 -- 2x+5
4. multiply by 50 -- 50(2x+5) = 100x + 250
5. add 1761 -- 100x + 250 + 1761 = 100x + 2011
6. I was born in 1940, so subtract that
100x + 2011 - 1940 = 100x + 71
So whatever you pick for x , would move into the hundreds position of your final answer.
Thus the first number is the choice , the last two numbers are the age.
The rules for step5 would change from year to year, in the next year (2012) we have to add 1762, etc.
1. First of all, pick the number of times a week that you would like to have chocolate (try for more than once but less than 10) 2. Multiply this number by 2 3. Add 5 4. Multiply it by 50 5. If you have already had your birthday this year add 1761 ; If you haven't, add 1760 6. Now subtract the four digit year that you were born You should have a three digit number The first digit of this was your original number (i.e. how many times you want to have chocolate each week) The next two numbers equal YOUR AGE! (Oh YES IT IS!!!)
1. Write a simplified function for the procedures taken in Chocolate Math. Use a variable to represent the number of times a person would like to have chocolate each week.
2. Write a simplified function that represents the number and a person’s age.
3. Prove algebraically that these two functions are equivalent.
The grading rubric is on the following page.
1 answer
1 answer