w=36/9
F = k(m1)(m2)/d^2
12 = k(3)(4)/9
1. Finf the width of a rectangle whose area is 36 sq in. And length is 9in.
2. The attraction F of any two masses m1 and m2 foe each other varies directly as the oroduct of the masses and inversely as the square of the distance d between these teo masses. Express the relation as an equation when the distance between the two masses is 3m and m1 is equal to 3 kg, m2 is equal to 4kg and F is equal to 12 N.
2 answers
Thanks Steve