3^(2x-y)=1
log base three, both sides, gives...
2x-y=0
and 16^(x/4)=8^(3x-y)
take log base 2 of each side
4(x/4)=3(3x-y)
x=9x-3y
8x-3y=0 and with
2x-y=0 solve.
1.find x and y if 3 raise to the power 2x-y equals 1 and 16 raise to the power x divided by 4 equals 8 raise to the power 3x-y
2. solve 2x-3y 2=x 2y-5=3x y?
2 answers
good luck with that.
I suspect a typo -- an ambiguity in the words.
poppy, fix the equations and you can arrive at a solution.
I suspect a typo -- an ambiguity in the words.
poppy, fix the equations and you can arrive at a solution.