1. Find two numbers whose sum is 84 and one number is 18 more than the other.
Answer: 84-18=2x x=33
84+18=2x x=51
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Oh my, you have me confused.
Either you wrote it wrong or you answered it wrong.
x + (x+18) = 84
2 x + 18 = 84
2 x = 66
x = 33
x+18 = 51
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2. A board 125 inches long is to be cut into two equal parts so that one part is 4 inches less than twice as long as the other part. Find the length of each part.
Answer :2x-4=125
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Nonsense - It would be unusual if they were equal and one was 4 inches less than twice the other
x and ( 2x-4)
x + (2x-4) = 125
3 x = 129
x = 43
2x-4 = 82
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3. Connie worked three more than twice as many hours as Gary did. How many hours did Connie work if together they worked 48 hours?
Answer:2x+3*2=48 NO
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Gary x
Connie ( 2 x + 3)
3 x + 3 = 48
3 x = 45
x = 15
connie = 2 x + 3 = 33
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4. The sum of the ages of Ruth and her Mother is 75 years. The difference in their ages is 29 years. How old is Ruth?
Answer:2x-29=75
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These are all the same, you please do some correctly now. x + (x+29)
5. Yolanda had three times as many nickels as dimes. If the total value of her coins was $1, how many nickels did she have?
Answer:x*3=1.00
6. The sum of $305 was divided among three people so that the second received $4 less than twice as much as the first, and the third received $23 more than the second. How much did each person receive?
This problem, I had no idea were to begin.
1. Find two numbers whose sum is 84 and one number is 18 more than the other.
Answer: 84-18=2x x=33
84+18=2x x=51
2. A board 125 inches long is to be cut into two equal parts so that one part is 4 inches less than twice as long as the other part. Find the length of each part.
Answer :2x-4=125
3. Connie worked three more than twice as many hours as Gary did. How many hours did Connie work if together they worked 48 hours?
Answer:2x+3*2=48
4. The sum of the ages of Ruth and her Mother is 75 years. The difference in their ages is 29 years. How old is Ruth?
Answer:2x-29=75
5. Yolanda had three times as many nickels as dimes. If the total value of her coins was $1, how many nickels did she have?
Answer:x*3=1.00
6. The sum of $305 was divided among three people so that the second received $4 less than twice as much as the first, and the third received $23 more than the second. How much did each person receive?
This problem, I had no idea were to begin.
3 answers
Well, 6 is a little different:
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6. The sum of $305 was divided among three people so that the second received $4 less than twice as much as the first, and the third received $23 more than the second. How much did each person receive?
first = x
second = 2x-4
third = 2x-4+23 = 2x + 19
x + (2x-4) + (2x+19) = 305
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6. The sum of $305 was divided among three people so that the second received $4 less than twice as much as the first, and the third received $23 more than the second. How much did each person receive?
first = x
second = 2x-4
third = 2x-4+23 = 2x + 19
x + (2x-4) + (2x+19) = 305
I'm still not exactly sure how to do it but the answer is
1)1st = $58; 2nd = $112; 3rd = $135
<3
<3
<3
:D
1)1st = $58; 2nd = $112; 3rd = $135
<3
<3
<3
:D