#1.using discs of thickness dy,
v = ∫[0,5] πr^2 dy
where r = 6-x = 6-y
v = ∫[0,5] π(6-y)^2 dy = 215π/3
using shells of thickness dx,
v1 = ∫[0,5] 2πrh dx
where r = 6-x and h = y = x
v1 = ∫[0,5] 2π(6-x)x dx = 200π/3
v2 is just a cylinder or radius 1 and height 5, or 5π
so the total volume is
v = v1 + v2 = 215π/3
Take a crack at the others. Post your work if you get stuck
Be sure to sketch the region, and watch for boundary changes.
1. Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the line x = 6.
y = x, y = 0, y = 5, x = 6
2. Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the specified axis.
y = 8 − x^2, y = x^2; about x = 2
3. The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any method.
x = (y − 6)^2, x = 1; about y = 5
1 answer