1).Find the sum of the n terms of the series Sn=1^2 + 3^2 +5^2+...+(2n-1)^2
2).Find the sum to n terms of 1/(1.2.3) + 3/(2.3.4) + 5/(3.4.5) + 7/(4.5.6) +....
3) Sum to n terms,the series 1.3.5 + 2.4.6 + 3.5.7 +.
3 answers
I answered the first part in your previous post
Still messing around with #2
#3,
∑ k(k+2)(k+4) , where k = 1 to n
if you expand this you will get a cubic , so you will have to have
∑ k^3 for k=1 to n equal to (1/4)n^2(n+1)^2
( I had to look that one up)
for the square and first degree terms use the ones I gave you in #1
good luck
#3,
∑ k(k+2)(k+4) , where k = 1 to n
if you expand this you will get a cubic , so you will have to have
∑ k^3 for k=1 to n equal to (1/4)n^2(n+1)^2
( I had to look that one up)
for the square and first degree terms use the ones I gave you in #1
good luck
n
∑ (2k-1)/[k(k+1)(k+2) =
k=1
n(3n+1)
--------------
4(n+1)(n+2)
∑ (2k-1)/[k(k+1)(k+2) =
k=1
n(3n+1)
--------------
4(n+1)(n+2)
1 answer