all look good, but I'm curious why you had negative angles for (a) annd (c).
For (a) I could see it, because the angle is greater than -pi
For (c) I would have added 2pi to get an angle less than pi, since the angle is in QII.
1. Find the modulus and argument of the following complex numbers, and write them in trigonometric form:
a. 5 – 8i
Answer = Sqrt{89} ( cos (-1.01219701) + i sin ( -1.01219701))
b. –1 – i
answer = Sqrt2 (cos (5pi/4) + i sin (5pi/4))
c. –5 + 12i
answer = 13 (cos ( -4.31759786068493) + i sin ( -4.31759786068493))
d. 1 + sqrt{3}i
answer = 2 ( cos (pi/3) + i sin (pi/3))
2 answers
I think he/she has a negative angle for a) by entering the data into a calculator and simply blindly accepting the answer the calculator gives.
Remember the calculator is programmed to give the closest angle to zero.
so tan^-1 (-8/5) = -1.012....
I would take 2π - 1.012....
Remember the calculator is programmed to give the closest angle to zero.
so tan^-1 (-8/5) = -1.012....
I would take 2π - 1.012....