The two questions are very similar in setup, I will do the first one, you do the second
length = integral √( 1 + (y')^2) dx from a to b
yours:
y = (2/3)x^(3/2) + 2
y' = x^(1/2)
(y')^2= x
length = integral √( 1 + x) dx from 14 to 16
= [ (2/3)(1+x)^(3/2) ] from 14 to 16
= (2/3)(17^(3/2) ) - (1/2)(15^(3/2) )
= appr 7.999
1.) Find the arc length y=2/3x ^3/2 + 2 over (14,16)
2.) Find the arc length y=8x^3/2+7 over (0,6)
1 answer
1 answer