1.Find a recurrence relation and initial conditions for sequences: 6,

13, 27, 55.

2.Write the first 4 terms in the sequence an+1 = 3an
2 -9 where n≥1 and a1=2.

1 answer

sure looks like a_n+1 = 2a_n + 1

really? You can't just plug in values for n?
If 3an
2
means 3an/2 then
a2 = 3a1/2-9 = 3*1-9 = -6

If not, you'll have to clean it up on your own
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